Joined Default Parameter

Discouraged explicit usage of the default separator

• Identifier: joined_default_parameter
• Enabled by default: No
• Supports autocorrection: Yes
• Kind: idiomatic
• Analyzer rule: No
• Minimum Swift compiler version: 5.0.0
• Default configuration:

  Key	Value
  severity	warning

Non Triggering Examples

let foo = bar.joined()

let foo = bar.joined(separator: ",")

let foo = bar.joined(separator: toto)

Triggering Examples

let foo = bar.joined(↓separator: "")

let foo = bar.filter(toto)
             .joined(↓separator: ""),

func foo() -> String {
  return ["1", "2"].joined(↓separator: "")
}